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为了计算B1:B5区域的平均值,以下公式中不正确的是()。
A.SUM(B1+B2+B3+B4+B5)/5
B.AVERAGE(B1:B5)/5
C.SUM(B1:B5)/5
D.SUM(B1,B2,B3,B4,B5)/5
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A.SUM(B1+B2+B3+B4+B5)/5
B.AVERAGE(B1:B5)/5
C.SUM(B1:B5)/5
D.SUM(B1,B2,B3,B4,B5)/5
下列不正确的公式或函数式是()
A.=SUM(B2:D2)
B.=SUM(B2,B5:C6)
C.=A1+B1+C1+E1
D.=C2><
(1)平均值mfcu=()。(单项选择题)
A.24.2
B.23.2
C.25.2
D.26.2
某工程混凝土结构设计强度等级为C25,结构实体检验留置的同条件养护试块为10组,试块取样、试压等符合规范的有关规定,各组试块的强度代表值分别为(MPa):23.5,20.6,26.5,25.4,23.8,25.3,24.5,27.1,23.2,22.3。计算并评定(λ1=1.70,λ2=0.90)
(1)平均值mfcu=()。(单项选择题)
A.24.2
B.23.2
C.25.2
D.26.2
(2)最小值fcu.min=()。(单项选择题)A.20.6
B.23.2
C.23.25
D.23.8
(3)标准差Sfcu=()。(单项选择题)A.1.852
B.1.962
C.2.226
D.2.325
(4)适用公式:平均值:()。(单项选择题)A.mfcu-λ1Sfcu≥9fcu.k
B.mfcux1.1-λSfcu≥0.9fcu.k
C.mfcu≥1.15fcu.k
D.mfcu×1.05-λ1Sfcu≥0.9λfcu,k
(5)适用公式:最小值:()。(单项选择题)A.fcu,min≥λ2fcu.k
B.fcu,min×1≥λ2fcu,k
C.mfcu≥0.95fcu.k
D.fcu.min×1.05≥λ2fcu,k
(6)综合评定混凝土强度()。(合格为A,不合格为B)A.合格
B.不合格
请帮忙给出每个问题的正确答案和分析,谢谢!
A.完全一样
B.稍小一些
C.稍大一些
D.可能大也可能小
A.资料的收集
B.选择作比较的交易实例
C.交易行为的补正及交易日期的修正
D.区域因素和个别因素的修正
E.运用市场法公式计算评估价
This view,【B7】is generally thought to be wrong. Specialists【B8】history and economics, have【B9】two things: that the period from 1640 to 1740 was【B10】by great poverty, and that industrialization certainly did not worsen and may have actually improved the conditions for the majority of the populace.
【B1】
A.admitted
B.believed
C.claimed
D.predicted